Find the volume of sphere having a radius of 15.37 cm3.
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The volume of a cube is (8x^3+60x^2+150x+125)cm3. Find the total surface area of 3 such cube given that x>0
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Gọi cạnh hình lập phương là \(a\left(cm\right)\)thể tích hình lập phương là \(V\left(cm^3\right)\).
Ta có: \(V=a^3\Rightarrow8x^3+60x^2+150x+125=a^3\)
\(\Rightarrow a^3=\left(2x+5\right)^3\Rightarrow a=2x+5\left(cm\right)\).
\(\Rightarrow\) Diện tích toàn phần của hình lập phương là: \(6a^2=6\left(2x+5\right)^2\left(cm^2\right)\).
\(\Rightarrow\) Diện tích toàn phần của 3 hình lập phương như thế là: \(3.6\left(2x+5\right)^2=18\left(2x+5\right)^2\left(cm^2\right)\).
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a ,find the volume of the whole figure in cm3
b , we paint every side of the figure except for the bottom side .how many cubes with side length 1 cm are there that have three faces painted ?
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A rectangular tank, measure 40 cm by 38 cm with a height of 30, is filled with water to a height of 10 cm.
a, Find the volume of water in the tank.
b, When 5 indentical iron balls are dropped into the tank, the water level increases to half of the tank. Find the volume of each iron ball.( giải bằng tiếng anh giúp! ><)
The volume of water in the tank :
40 x 38 x 10 = 15200 cm3
The volume of each iron ball is :
(40 x 38 x ( 30 : 2 ) -15200 ):5=1520 ( cm3 )
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In order to increase the volume of a cuboid tank, peole increase the length of the tank and keep the width and the height unchanged. The area of the base increases by 75% and the tank can contain 1500 more liters of water. Find the volume of the tank before change?
In order to increase the volume of a cuboid tank , people increase the length of the tank and keep the width nd the height unchanged . The area of the base increase by 75% and the tank can contain 1500 more liters of water . Find the volume of the tank before change?
In order to increase the volume of a cuboid tank, people increase the length of the tank and keep the width and the height unchanged. The area of the base increases by 75 % and the tank can contain 1500 more liters of water. Find the volume of the tank before change ?
1: the perimeter of a circle is 15,7 dm. Itss area is...cm22: the ratio of the number of girls to the number of boys in a classroom is 5:4. When 10 girls left the classroom, the ratio of the number of boys to the number of girls became 4:3. How many students were in the classroom at first?3: 47/250 dm3...cm34: At the party 60% of the boys are dancing with 80% of the girls. How many people are dancing if there are 35 people ( A pair cludes only one boy and one girl)5: An aquarium is 8dm deep, 12...
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1: the perimeter of a circle is 15,7 dm. Its's area is...cm2
2: the ratio of the number of girls to the number of boys in a classroom is 5:4. When 10 girls left the classroom, the ratio of the number of boys to the number of girls became 4:3. How many students were in the classroom at first?
3: 47/250 dm3=...cm3
4: At the party 60% of the boys are dancing with 80% of the girls. How many people are dancing if there are 35 people ( A pair cludes only one boy and one girl)
5: An aquarium is 8dm deep, 12 dm long and 0,3 m wide. What is the volume of the aquarium in cubic centimeter?. Answer: the volume of the aquarium is...cm3
1962,5 cm245 học sinh188 cm324 người288000 cm3
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1962,5 cm2
45 học sinh
188 cm3
24 người
288000 cm3
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Find the area of a circle with a radius of 2cm.
Answer: The area of a circle is: ............
find the volume of a pyramid such that the base area is 100cm2 and the height is 9cm
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- Trans: Tìm thể tích của hình chóp sao cho diện tích đáy là 100cm2 và chiều cao là 9cm.
\(S=\dfrac{1}{3}.h.S_{\text{Đáy}}=\dfrac{1}{3}.9.100=300(cm^3)\)
Vậy \(S=300cm^3\)
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The volume of the pyramid:
\(\dfrac{1}{3}.100.9=300\left(cm^3\right)\)
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find the area of equilateral triangle inscribed in a circle of radius 6cm
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- Trans: Tìm diện tích tam giác đều nội tiếp đường tròn bán kính 6cm.
Giả sử ta có \(ΔABC \) nội tiếp \(O;6cm)\) và \(AB=AC=BC=x(cm)\)
Xét \(ΔABC\) đều có: \(O\) là trọng tâm tam giác
\(\Rightarrow \dfrac{AO}{AH}=\dfrac{2}{3}\) (H là hình chiếu của A trên BC)
Mà \(AO=R=6cm \Rightarrow AH=9(cm)\)
Áp dụng định lý Pytago vào \(ΔACH\) có:
\(AC^2 =AH^2+CH^2 \\ \Leftrightarrow x^2 = 9^2 + (\dfrac{x}{2})^2 \\ \Leftrightarrow x=6\sqrt{3}\)
\(\Rightarrow S_{ΔABC}=\dfrac{1}{2} AH.BC=\dfrac{1}{2} . 9.6\sqrt3 = 27\sqrt3 (cm^2)\)
Vậy \(S=27\sqrt{3}cm^2\)
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